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Topic 6

Space physics

Cambridge IGCSE Physics 0625 · Core and Extended, with Extended-only material marked

This topic is a recent addition to the syllabus. If your notes or past papers have no astronomy in them at all, they are out of date.

🎯What you need to be able to do

  • Explain day, night, the year and the phases of the Moon in terms of rotation and orbits.
  • Describe the Solar System and how the planets are held in orbit.
  • Describe the Sun as a star, and the life cycle of stars of different masses.
  • Describe the Milky Way and use the light-year.
  • Explain redshift as evidence for an expanding universe and for the Big Bang.
  • EXTENDEDUse \( v = 2\pi r/T \), and use the Hubble constant to estimate the age of the Universe.

📚The physics

Why we have days, years and Moon phases. The Earth rotates on its axis once every 24 hours, which gives day and night. The Earth orbits the Sun once every 365¼ days, which gives the year — and the quarter is why we need leap years. The Moon orbits the Earth about once a month, and we see phases because we see different amounts of its sunlit half from where we stand. The Moon is not changing shape and the Earth’s shadow is not involved; that is a lunar eclipse, which is a different and much rarer thing.

The Solar System has eight planets. In order out from the Sun: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune. The four inner ones are small and rocky; the four outer ones are large and gaseous, because the young Sun’s heat drove the lighter material outwards before the planets formed. Everything formed from a rotating cloud of gas and dust pulled together by gravity, which is why nearly all the orbits lie in one plane and go the same way round.

What keeps a planet in orbit is the gravitational attraction of the Sun, acting towards the centre. Orbits are ellipses rather than perfect circles, though most are close to circular. Planets further from the Sun travel more slowly and have much longer years — Neptune takes 165 Earth years to go round once.

EXTENDED For a roughly circular orbit the speed is \( v = \dfrac{2\pi r}{T} \), since \( 2\pi r \) is the circumference and \(T\) is the time for one lap.

The Sun is a star of medium size, made mostly of hydrogen and helium. It releases energy by nuclear fusion in its core, and radiates most strongly in the visible and infrared parts of the spectrum.

The life cycle of a star. All stars begin as a nebula, a cloud of gas and dust that gravity pulls together into a protostar. When the core gets hot enough for fusion, the star becomes stable — it stays that way for most of its life because the inward pull of gravity is balanced by the outward push from the hot core. What happens next depends on mass:

  • A star like the Sun swells into a red giant, then sheds its outer layers as a planetary nebula and leaves a white dwarf.
  • A much more massive star swells into a red supergiant, then explodes as a supernova, leaving a neutron star or, if massive enough, a black hole.

Supernovae matter beyond the exam: they are where elements heavier than iron are made, and they scatter them into space. The iron in your blood was made in a star that exploded.

The Milky Way is our galaxy: a spiral containing hundreds of billions of stars, with the Sun somewhere in one of its arms. Distances are measured in light-years — the distance light travels in a year, about \( 9.5 \times 10^{15} \) m. A light-year is a distance, not a time, and saying otherwise is a guaranteed lost mark.

Redshift and the Big Bang. Light from distant galaxies is shifted towards the red end of the spectrum, and the further away a galaxy is, the greater its redshift. That means distant galaxies are moving away from us, and faster the further they are. It does not mean we are at the centre of anything — space itself is expanding, so every observer anywhere sees the same thing. Running that expansion backwards gives the Big Bang.

EXTENDED The Hubble constant \( H_0 \) relates a galaxy’s speed to its distance, \( v = H_0 d \). Rearranged as \( d/v = 1/H_0 \), that ratio is roughly the time since everything was in the same place — an estimate of the age of the Universe.

✏️Worked example

EXTENDED A galaxy is \( 4.2 \times 10^{24} \) m away and is receding at \( 9.8 \times 10^{6} \) m s\(^{-1}\).

(a) Find the Hubble constant. \( H_0 = v/d = \dfrac{9.8 \times 10^{6}}{4.2 \times 10^{24}} = 2.3 \times 10^{-18} \) s\(^{-1}\). The unit looks strange because distance divided by speed leaves only time.

(b) Estimate the age of the Universe. \( 1/H_0 = 1/(2.3 \times 10^{-18}) = 4.3 \times 10^{17} \) s. Converting: \( 4.3 \times 10^{17} \div (60 \times 60 \times 24 \times 365) \approx 1.4 \times 10^{10} \) years, or 14 billion years.

Check it against what you know. The accepted age is about 13.8 billion years, so this is right. If your answer comes out as thousands or as billions of billions, you have almost certainly slipped on a power of ten — write every number in standard form before dividing.

🔭See it happen

On a clear night, find the Andromeda galaxy — visible as a faint smudge from a dark site. The light entering your eye left it about 2.5 million years ago, before our species existed. That is what a light-year means, and no diagram conveys it as well.

📝Practise

Worksheet 6 — to be linked.

🔗Go deeper — other people’s work

These are external resources, not mine. If one stops working, tell me and everything above it on this page still stands.

  • NASA — Solar System exploration, and the life cycles of stars
  • BBC Bitesize — Space physics