Inheritance
🎯What you need to be able to do
- Explain inheritance through haploid gametes and a diploid zygote.
- Describe how genetic crosses are carried out in flowering plants, using the terms P, F1, F2 and Punnett grid.
- Use the terms genotype, phenotype, allele, homozygous, heterozygous, dominant and recessive; explain phenotypic plasticity.
- Explain phenylketonuria, multiple alleles and ABO blood groups, codominance and incomplete dominance.
- Explain sex determination and sex linkage, using haemophilia, and deduce patterns of inheritance from pedigree charts.
- Explain continuous variation due to polygenic inheritance and environment, and construct and interpret box-and-whisker plots.
- AHL Explain independent assortment, and predict 9:3:3:1 and 1:1:1:1 ratios with dihybrid Punnett grids.
- AHL Explain autosomal linkage and recombinants, and use a chi-squared test on dihybrid cross data.
📚The biology
Gametes and zygotes
In every eukaryote with a sexual life cycle, inheritance follows the same pattern. Each parent produces haploid gametes by meiosis, carrying one copy of each gene. At fertilization two gametes fuse to form a diploid zygote, which therefore has two copies of each autosomal gene — one from each parent. (Autosomes are all the chromosomes other than the sex chromosomes.)
Genetic crosses in flowering plants
Pollen contains the male gametes and the female gametes are in ovules inside the ovary, so a cross is made by pollination: pollen from one chosen plant is transferred to the stigma of another. Plants such as peas produce both male and female gametes on the same plant, so they can self-pollinate and therefore self-fertilize. To make a controlled cross, the anthers of the female parent are removed before they release pollen, and the flower is covered to prevent stray pollen arriving.
the parents of a cross
the offspring of the P generation (first filial)
the offspring of crossing or self-pollinating the F1
a table with the gametes of one parent along the top and the other down the side, showing all possible offspring genotypes
Genetic crosses are widely used to breed new varieties of crop and ornamental plants.
Genes, alleles and genotype
A gene is a heritable factor that influences a characteristic, found at a particular position (locus) on a chromosome. Alleles are different versions of the same gene, differing slightly in base sequence. The genotype is the combination of alleles an organism has for a gene.
two identical alleles of a gene (e.g. TT or tt)
two different alleles of a gene (e.g. Tt)
Phenotype
The phenotype is the set of observable traits of an organism, resulting from its genotype and environmental factors. In humans:
ABO blood group; eye colour largely; phenylketonuria.
scars; tattoos; a language spoken.
height (genes and nutrition); skin colour (genes and sun exposure); body mass.
Dominant and recessive alleles
A dominant allele affects the phenotype whenever it is present, in one or two copies. A recessive allele only affects the phenotype when no dominant allele is present, that is, in the homozygous recessive. Dominant alleles are written with a capital letter, recessive with the lower-case version of the same letter.
Why does a heterozygote look the same as a homozygous dominant? Usually the dominant allele codes for a functional protein such as an enzyme, and the recessive allele codes for a non-functional version or none at all. One copy of the dominant allele produces enough functional protein to give the full phenotype, so TT and Tt look identical.
Phenotypic plasticity
Phenotypic plasticity is the capacity of an organism to develop traits suited to the environment it experiences, by varying patterns of gene expression. It is not due to a change in genotype, and the changes may be reversible during an individual’s life. Examples: human skin tanning with sun exposure; muscles enlarging with exercise; some plants producing thinner, broader leaves in shade.
Phenylketonuria
Phenylketonuria (PKU) is a recessive genetic condition caused by a mutation in an autosomal gene coding for the enzyme that converts the amino acid phenylalanine to tyrosine. Only people homozygous for the recessive allele are affected: they cannot make the functional enzyme, phenylalanine accumulates in the blood and damages the developing brain. Heterozygous carriers have one working allele and are unaffected. Newborns are screened, and affected children follow a low-phenylalanine diet, which prevents brain damage.
SNPs and multiple alleles
Each base substitution that becomes established in a population is a single-nucleotide polymorphism (D1.3). Over time, many different alleles of a gene can accumulate. Any number of alleles of a gene can exist in the gene pool of a population, but an individual diploid organism inherits only two.
ABO blood groups: multiple alleles
The ABO blood group gene has three alleles: IA, IB and i. IA and IB are codominant with each other, and both are dominant to i.
IAIA or IAi
IBIB or IBi
IAIB
ii
Codominance and incomplete dominance
Both alleles are fully expressed in the heterozygote, which has a dual phenotype showing both traits. Example: blood group AB (IAIB): red blood cells carry both A and B antigens.
Neither allele is fully dominant; the heterozygote has an intermediate phenotype. Example: the four o’clock flower (Mirabilis jalapa): red × white gives pink offspring. Crossing two pinks gives red : pink : white in a 1 : 2 : 1 ratio.
Sex determination and sex chromosomes
Humans have 22 pairs of autosomes and one pair of sex chromosomes: typical female bodies have XX and typical male bodies XY. All eggs carry an X chromosome; sperm carry either an X or a Y. So the sex chromosome in the sperm determines whether the zygote develops certain male-typical physical characteristics (Y, due to a gene on the Y chromosome that triggers development of testes) or female-typical ones (X). The ratio is expected to be 1 : 1.
The X chromosome is much larger and carries far more genes (over 800 coding for proteins) than the Y chromosome (under 100). Genes carried on the X are sex-linked. Because males have only one X, any recessive allele on it is expressed.
Haemophilia
Haemophilia is a sex-linked recessive disorder in which blood fails to clot properly, because a gene on the X chromosome coding for a clotting factor is faulty. Alleles on the X chromosome are shown as superscripts on an uppercase X: XH (normal) and Xh (haemophilia).
XHXH unaffected
XHXh unaffected carrier
XhXh affected (rare)
XHY unaffected
XhY affected (no second X to mask it)
Haemophilia is far more common in males. An affected male cannot pass it to his sons (they get his Y) but all his daughters will be carriers.
Pedigree charts
A pedigree chart shows the inheritance of a condition in a family: circles for females, squares for males, shaded for affected, horizontal lines joining parents, vertical lines to children. Reasoning from the chart:
- Recessive: two unaffected parents have an affected child — both parents must be carriers.
- Dominant: two affected parents have an unaffected child; and every affected person has at least one affected parent.
- Sex-linked recessive: mostly affected males; affected sons of unaffected (carrier) mothers; never passed from father to son.
This uses both kinds of reasoning. Seeing a pattern in some families and generalizing (“this condition is recessive”) is inductive reasoning. Then applying that conclusion to deduce the genotypes of particular individuals in the chart is deductive reasoning.
Pedigrees also show why many societies prohibit marriage between close relatives. Relatives are more likely to carry the same rare recessive alleles, inherited from a common ancestor, so their children have a higher probability of being homozygous recessive for a harmful condition.
Continuous variation
Fall into distinct categories with no intermediates. Usually controlled by one gene with little environmental effect. Example: ABO blood group.
Show a range of values, often forming a normal distribution. Result from polygenic inheritance (many genes, each with a small additive effect) and/or environmental factors. Example: human skin colour, controlled by several genes affecting melanin production, and by sun exposure.
Continuous data are summarized with measures of central tendency: the mean (sum of values ÷ number of values), the median (middle value when ordered) and the mode (most frequent value).
Box-and-whisker plots
A box-and-whisker plot displays the distribution of a continuous variable, such as student height, showing six features:
lowest value that is not an outlier (end of lower whisker)
lower edge of the box: 25% of values are below it
line inside the box
upper edge of the box: 75% of values are below it
highest value that is not an outlier (end of upper whisker)
plotted as separate points
The interquartile range (IQR) = Q3 − Q1. A data point is an outlier if it is more than 1.5 × IQR above Q3 or below Q1.
Segregation and independent assortment AHL
The movements of chromosomes in meiosis explain the outcomes of crosses:
- Segregation: the two alleles of a gene, on a pair of homologous chromosomes, separate into different gametes when homologues separate in meiosis I.
- Independent assortment: for two genes on different chromosomes (unlinked), the orientation of one bivalent at metaphase I is independent of the other. So the allele a gamete receives for one gene does not affect which allele it receives for the other. An individual AaBb produces four types of gamete — AB, Ab, aB, ab — in equal proportions.
Dihybrid crosses AHL
A dihybrid cross follows two genes at once. With two unlinked autosomal genes:
Each parent makes 4 gametes in equal proportions, giving a 4 × 4 Punnett grid of 16 squares. Phenotypes: both dominant traits 9 : dominant A only 3 : dominant B only 3 : both recessive 1.
The heterozygote makes 4 gametes in equal proportions; the homozygous recessive makes only ab. Phenotypes: 1 : 1 : 1 : 1.
The 9:3:3:1 and 1:1:1:1 ratios depend on what has been called Mendel’s second law, independent assortment. This “law” only applies if the genes are on different chromosomes, or so far apart on one chromosome that crossing over separates them half the time (a 50% recombination rate). Like other biological “laws”, it has exceptions.
Gene loci in databases AHL
Online databases such as those of the NCBI and Ensembl give the locus (chromosome and position) of each human gene and the polypeptide it codes for. Exploring them, you can find pairs of genes on different chromosomes, which will assort independently, and pairs close together on the same chromosome, which will tend to be inherited together.
Autosomal gene linkage AHL
Linked genes are genes located on the same chromosome. They do not assort independently, because they tend to be inherited together: they move as one unit when the chromosome moves in meiosis. The closer together they are, the more strongly linked.
When showing linked genes, write the alleles alongside vertical lines representing the two homologous chromosomes, so that it is clear which alleles are on the same chromosome. For example, a heterozygote with A and B on one chromosome and a and b on the other is shown with A above B on the left line and a above b on the right line.
Recombinants AHL
In a cross between an individual heterozygous for both genes and one homozygous recessive for both:
- If the genes are unlinked, the heterozygote produces four gamete types equally, and offspring appear in a 1:1:1:1 ratio.
- If the genes are linked, the heterozygote mostly produces gametes with the parental combinations of alleles (AB and ab in the example above). Only when crossing over occurs between the two loci are recombinant gametes (Ab and aB) produced, and these are less common.
Recombinants are gametes, genotypes or phenotypes with a combination of alleles different from either parent. In a test cross with linked genes, the two parental phenotypes are most common and the two recombinant phenotypes are least common.
Chi-squared test on dihybrid data AHL
Observed results never match expected ratios exactly, because of chance. The chi-squared test decides whether a difference between observed and expected results is small enough to be due to chance or is statistically significant.
- State a null hypothesis: there is no significant difference between observed and expected results (e.g. the genes are unlinked and assort independently). The alternative hypothesis is that there is a significant difference.
- Calculate expected numbers from the predicted ratio and the total.
- Calculate \( \chi^{2} = \sum \dfrac{(O - E)^{2}}{E} \).
- Degrees of freedom = number of categories − 1 (for four phenotypes, 3).
- Compare with the critical value at the p = 0.05 significance level (7.815 for 3 degrees of freedom). If \( \chi^{2} \) is less, accept the null hypothesis; if it is greater, reject it.
The F2 generation is a sample used to represent all possible offspring. p = 0.05 means there is a 5% probability that a difference this large would arise by chance alone if the null hypothesis were true.
✏️Worked example
(b) AHL In pea plants, round seed (R) is dominant to wrinkled (r) and yellow seed (Y) is dominant to green (y). Plants heterozygous for both genes were self-pollinated. The F2 contained 315 round yellow, 108 round green, 101 wrinkled yellow and 32 wrinkled green. Use a chi-squared test to decide whether the results fit a 9:3:3:1 ratio.
(a) Parents: XHXh × XHY. Gametes: mother XH or Xh; father XH or Y.
XHXH — unaffected girl
XHXh — carrier girl
XHY — unaffected boy
XhY — affected boy
Probability that a child is an affected boy = 1/4 (25%). Probability that a son is affected = 1 of the 2 boys = 1/2 (50%).
(b) Null hypothesis: the genes assort independently, so there is no significant difference from a 9:3:3:1 ratio. Total = 556.
O = 315, E = 9/16 × 556 = 312.75
(O − E)2/E = 0.016
O = 108, E = 3/16 × 556 = 104.25
(O − E)2/E = 0.135
O = 101, E = 104.25
(O − E)2/E = 0.101
O = 32, E = 1/16 × 556 = 34.75
(O − E)2/E = 0.218
Degrees of freedom = 4 − 1 = 3; critical value at p = 0.05 is 7.815. Since 0.47 < 7.815, accept the null hypothesis: the differences are not significant and can be attributed to chance. The results fit a 9:3:3:1 ratio, consistent with the genes being unlinked.
📝Practise
Work through these on paper, then reveal the answer. Questions 5 and 6 are AHL.
1. Two parents both have blood group A. Their child has blood group O. Deduce the genotypes of the parents and the probability that their next child has blood group O.
2. Distinguish between codominance and incomplete dominance, with an example of each.
3. In a pedigree, two unaffected parents have an affected daughter. Deduce, with reasons, whether the condition is dominant or recessive, and whether it could be sex-linked.
4. The heights of 13 students have Q1 = 160 cm, median = 163 cm and Q3 = 168 cm. The shortest student is 148 cm and the tallest is 190 cm. Determine whether either is an outlier.
5. AHL Explain why a dihybrid cross between two double heterozygotes gives a 9:3:3:1 ratio only if the genes are unlinked.
6. AHL In a test cross AaBb × aabb, the offspring were 42 AaBb, 40 aabb, 9 Aabb and 9 aaBb. Explain these results.
🔗Go deeper — other people’s work
These are external resources, not mine. If one stops working, tell me and everything above it on this page still stands.
- NCBI Gene and Ensembl — databases showing the chromosomal locus and protein product of every human gene.
- Learn.Genetics (University of Utah) — interactive pedigree and heredity activities.
- HHMI BioInteractive — genetics problem sets with worked chi-squared analyses.