HomeLearning HubA Level ChemistryA2 33: Carboxylic acids and derivatives
A2 33

Carboxylic acids and derivatives

A Level · Organic chemistry · Paper 4 · builds on AS 18

🎯What you need to be able to do

  • Recall how benzoic acid is made from methylbenzene.
  • Describe how carboxylic acids are converted into acyl chlorides with PCl3 and heat, PCl5 or SOCl2.
  • Recognise that methanoic acid and ethanedioic acid can be oxidised further, to carbon dioxide.
  • Describe and explain the relative acidities of carboxylic acids, phenols and alcohols, and of chlorine-substituted carboxylic acids.
  • Recall how esters are made from acyl chlorides (ethyl ethanoate, phenyl benzoate).
  • Describe the reactions of acyl chlorides with water, alcohols, phenol, ammonia and amines, and the addition–elimination mechanism.
  • Explain the relative ease of hydrolysis of acyl chlorides, alkyl chlorides and aryl chlorides.

📚The chemistry

33.1 Carboxylic acids

Making benzoic acid

Heat an alkylbenzene such as methylbenzene with hot alkaline KMnO4, then acidify with dilute acid (topic 30): C6H5CH3 + 3[O] → C6H5COOH + H2O.

Making acyl chlorides

The OH of the carboxyl group is replaced by Cl — the same three reagents that convert alcohols to chloroalkanes:

\[ \mathrm{CH_3COOH + PCl_5 \rightarrow CH_3COCl + POCl_3 + HCl} \] \[ \mathrm{3CH_3COOH + PCl_3 \rightarrow 3CH_3COCl + H_3PO_3} \quad \text{(heat)} \] \[ \mathrm{CH_3COOH + SOCl_2 \rightarrow CH_3COCl + SO_2 + HCl} \]

Acids that can be oxidised further

Most carboxylic acids resist oxidation, but two do not:

  • Methanoic acid, HCOOH, contains an H–C=O group, like an aldehyde. It is oxidised to CO2 and H2O by Fehling’s or Tollens’ reagent (giving a brick-red precipitate or silver mirror, the only acid that does), or by acidified KMnO4 or K2Cr2O7: HCOOH + [O] → CO2 + H2O.
  • Ethanedioic acid, HOOCCOOH, is oxidised by warm acidified KMnO4 to carbon dioxide: HOOCCOOH + [O] → 2CO2 + H2O. This is the basis of the manganate(VII)–ethanedioate titration (topic 28).

Acidity: acids, phenols and alcohols

\[ \text{alcohols} \; < \; \text{water} \; < \; \text{phenols} \; < \; \text{carboxylic acids} \]

Each is judged by the stability of its anion:

  • Carboxylate ion, RCOO: the negative charge is delocalised over two oxygen atoms (both C–O bonds become identical). Two electronegative atoms share the charge, so the ion is very stable, and carboxylic acids are the strongest of the group — strong enough to react with carbonates.
  • Phenoxide ion: the charge is delocalised into the ring, but the ring’s carbon atoms are much less electronegative than oxygen, so this spreads the charge less effectively. Phenol is weaker than carboxylic acids (topic 32).
  • Alkoxide ion: no delocalisation, and the alkyl group’s electron-donating effect intensifies the charge. Alcohols are the weakest.

Chlorine-substituted acids

Replacing H atoms in the alkyl group with chlorine makes the acid stronger (approximate pKa values; sources differ slightly, and a question will give its own):

CH3COOH — pKa 4.76
CH2ClCOOH — pKa 2.86
CHCl2COOH — pKa 1.29
CCl3COOH — pKa 0.65

Chlorine is electronegative: it withdraws electron density from the carboxylate group through the chain (a negative inductive effect). This spreads out the negative charge on the carboxylate ion and stabilises it, so the acid dissociates more. More chlorine atoms mean more withdrawal and a stronger acid. The effect also weakens with distance: a Cl on the carbon next to COOH strengthens the acid more than one further along the chain (2-chlorobutanoic acid is stronger than 4-chlorobutanoic acid).

33.2–33.3 Acyl chlorides and esters

An acyl chloride, RCOCl, is the most reactive derivative of a carboxylic acid. The carbonyl carbon is bonded to two electronegative atoms, O and Cl, which both pull electron density away from it, so it is strongly δ+. Acyl chlorides react rapidly at room temperature with nucleophiles, always releasing steamy fumes of HCl:

  • Water — hydrolysis to the carboxylic acid (violent, fuming): \[ \mathrm{CH_3COCl + H_2O \rightarrow CH_3COOH + HCl} \]
  • Alcohol — an ester: \[ \mathrm{CH_3COCl + C_2H_5OH \rightarrow CH_3COOC_2H_5 + HCl} \quad \text{ethyl ethanoate} \]
  • Phenol — an ester. Phenols do not form esters well with carboxylic acids, so an acyl chloride is the way to make them: \[ \mathrm{C_6H_5COCl + C_6H_5OH \rightarrow C_6H_5COOC_6H_5 + HCl} \quad \text{phenyl benzoate} \]
  • Ammonia — a primary amide (the HCl then reacts with excess ammonia to form NH4Cl): \[ \mathrm{CH_3COCl + NH_3 \rightarrow CH_3CONH_2 + HCl} \quad \text{ethanamide} \]
  • Primary or secondary amine — a substituted amide: \[ \mathrm{CH_3COCl + CH_3NH_2 \rightarrow CH_3CONHCH_3 + HCl} \quad \text{N-methylethanamide} \]

The addition–elimination mechanism

All five reactions follow the same two stages. For ethanoyl chloride with water:

  1. Addition: curly arrow from a lone pair on the O of water to the δ+ carbonyl carbon; curly arrow from the C=O π bond to the oxygen. This gives a tetrahedral intermediate, with O and a positively charged OH2+ group.
  2. Elimination: curly arrow from a lone pair on O back to reform the C=O bond; curly arrow from the C–Cl bond to Cl, which leaves as Cl. Then H+ is lost from the OH2+, and it combines with Cl to form HCl.

With an alcohol, ammonia or an amine the nucleophile is ROH, NH3 or RNH2 instead; the steps are identical.

Addition-elimination between ethanoyl chloride and water. A lone pair on the water oxygen attacks the delta-plus carbonyl carbon while the carbon-oxygen pi bond moves onto the oxygen, giving a tetrahedral intermediate with a negative oxygen and a positive OH2 group. A lone pair on the negative oxygen then re-forms the carbon-oxygen double bond, the carbon-chlorine bond breaks so chloride leaves, and a hydrogen ion is lost, giving ethanoic acid and hydrogen chloride.
Addition–elimination: the nucleophile adds to the carbonyl carbon, then chloride is eliminated as C=O re-forms.

Ease of hydrolysis

\[ \text{acyl chlorides} \; > \; \text{alkyl chlorides} \; > \; \text{aryl chlorides} \]
  • Acyl chlorides are hydrolysed by cold water, instantly. The carbonyl carbon is very δ+ (bonded to both O and Cl), and it is planar and unhindered, so the nucleophile can easily attack by addition.
  • Alkyl chlorides need warm aqueous alkali (or are hydrolysed slowly by water, as in the silver nitrate test). Their carbon is less δ+ (only one electronegative atom), and attack requires breaking a C–Cl bond at the same time (topic 15).
  • Aryl chlorides are not hydrolysed under normal conditions: the C–Cl bond is strengthened by overlap with the ring’s π system, and the π electrons repel nucleophiles (topic 31).

✏️Worked example

3.93 g of ethanoyl chloride is added to excess water. (a) Describe what you would see and write the equation. (b) Calculate the volume of 2.00 mol dm−3 NaOH needed to neutralise the resulting solution. [Mr: CH3COCl 78.5] (c) Name the organic product when ethanoyl chloride reacts with (i) propan-1-ol; (ii) phenol; (iii) ethylamine. (d) Explain why chloroethanoic acid is a stronger acid than ethanoic acid.

(a) A violent reaction at room temperature, with steamy (white) fumes of HCl:

\[ \mathrm{CH_3COCl + H_2O \rightarrow CH_3COOH + HCl} \]

(b) Both products are acids. n(CH3COCl) = 3.93 / 78.5 = 0.0501 mol, giving 0.0501 mol of CH3COOH and 0.0501 mol of HCl, each of which reacts 1 : 1 with NaOH.

\[ n(\mathrm{NaOH}) = 2 \times 0.0501 = 0.100\ \mathrm{mol} \qquad V = \frac{0.100}{2.00} = 0.0500\ \mathrm{dm^3} = 50.0\ \mathrm{cm^3} \]

(c)(i) Propyl ethanoate, CH3COOCH2CH2CH3. (ii) Phenyl ethanoate, CH3COOC6H5. (iii) N-ethylethanamide, CH3CONHC2H5.

(d) The chlorine atom is electronegative and withdraws electron density from the COO group of the anion. This spreads the negative charge further and stabilises the chloroethanoate ion, so the acid dissociates more readily: a larger Ka (pKa 2.86 against 4.76).

Check it. The key point in (b) is that two acids form. If you only counted the ethanoic acid, the answer would be 25.0 cm3 — exactly half. A result that is a neat factor of two away from yours is a sign that one product has been missed.
Forgetting the HCl, or naming amides wrongly. Every acyl chloride reaction releases HCl, which is an acid, a fume and (with ammonia or amines) a reactant for the excess base. And the group on the nitrogen of a substituted amide is shown with N-: CH3CONHC2H5 is N-ethylethanamide, not “ethyl ethanamide”.

📝Practise

Work through these, then reveal the answer. Each question targets a different objective from the list above.

1. Give three reagents that convert benzoic acid into benzoyl chloride, with an equation for one.
PCl5 (room temperature), PCl3 (heat) or SOCl2. For example: C6H5COOH + SOCl2 → C6H5COCl + SO2 + HCl. (SOCl2 is convenient because both by-products are gases.)
2. Explain why methanoic acid gives a silver mirror with Tollens’ reagent but ethanoic acid does not.
Methanoic acid, HCOOH, has an H atom attached to the carbonyl carbon — the same H–C=O arrangement as an aldehyde. It can be oxidised (to CO2 and H2O), and in doing so reduces Ag+ to silver. Ethanoic acid, CH3COOH, has no H on the carbonyl carbon and cannot be oxidised by mild oxidising agents, so there is no reaction.
3. Place in order of increasing acidity, and explain: CH3COOH, CCl3COOH, CH2ClCOOH, C6H5OH.
C6H5OH < CH3COOH < CH2ClCOOH < CCl3COOH. Phenol is weakest: its anion’s charge is delocalised into the ring of carbon atoms, less effective than delocalisation over two oxygens as in a carboxylate. Among the acids, each electronegative Cl atom withdraws electron density from the carboxylate group, spreading and stabilising its charge; three Cl atoms do this most, so trichloroethanoic acid is the strongest.
4. Describe the mechanism for the reaction of ethanoyl chloride with methanol.
Addition–elimination. A lone pair on the oxygen of CH3OH attacks the δ+ carbonyl carbon (curly arrow from the lone pair to C), and the C=O π electrons move onto the oxygen (arrow from the π bond to O), giving a tetrahedral intermediate. The O lone pair then reforms C=O while the C–Cl bond breaks (arrow from the bond to Cl), expelling Cl. Loss of H+ from the attached O(H)CH3 group gives methyl ethanoate, CH3COOCH3, and HCl.
5. Compare what happens when water is added to ethanoyl chloride, chloroethane and chlorobenzene, and explain.
Ethanoyl chloride: vigorous reaction at room temperature, steamy fumes of HCl. Chloroethane: very slow hydrolysis (needs warming with alkali to be useful). Chlorobenzene: no reaction. The acyl chloride’s carbonyl carbon is highly δ+ (bonded to O and Cl) and planar, so water adds easily. Chloroethane’s carbon is less δ+ and the C–Cl bond must break as the nucleophile attacks. Chlorobenzene’s C–Cl bond is strengthened by delocalisation into the ring, and the π electrons repel nucleophiles.
6. Explain why phenyl benzoate is made from benzoyl chloride and phenol rather than from benzoic acid and phenol.
Phenol is a poor nucleophile towards carboxylic acids: the lone pair on its oxygen is partly delocalised into the ring, so it is less available, and the acid’s carbonyl carbon is only weakly δ+. The equilibrium for direct esterification lies far to the left. Benzoyl chloride has a much more δ+ carbonyl carbon and a good leaving group (Cl), so it reacts with phenol rapidly and irreversibly at room temperature: C6H5COCl + C6H5OH → C6H5COOC6H5 + HCl.

🔗Go deeper — other people’s work

These are external resources, not mine. If one stops working, tell me and everything above it on this page still stands.

  • Chemguide (Jim Clark) — the acyl chlorides section, with the addition–elimination mechanism for each nucleophile