HomeLearning HubA Level ChemistryA2 34: Nitrogen compounds
A2 34

Nitrogen compounds

A Level · Organic chemistry · Paper 4 · builds on AS 19

🎯What you need to be able to do

  • Recall how primary and secondary amines are made: from halogenoalkanes with ammonia or amines, and by reducing amides and nitriles.
  • Describe amide formation from acyl chlorides, and explain the basicity of amines.
  • Describe making phenylamine from benzene, its reaction with bromine water and with nitrous acid, and the relative basicities of ammonia, ethylamine and phenylamine.
  • Describe azo coupling and the use of azo compounds as dyes.
  • Describe the hydrolysis and reduction of amides, and explain why amides are much weaker bases than amines.
  • Describe the acid–base properties of amino acids, zwitterions and the isoelectric point; peptide bond formation; and interpret electrophoresis.

📚The chemistry

34.1 Primary and secondary amines

An amine is a derivative of ammonia with one or more H atoms replaced by alkyl or aryl groups: primary RNH2, secondary R2NH, tertiary R3N.

Making them

  • Halogenoalkane + ammonia in ethanol, heated under pressure (sealed tube) → primary amine (topic 19).
  • Halogenoalkane + primary amine in ethanol, heated in a sealed tube → secondary amine: CH3CH2Br + CH3NH2 → CH3CH2NHCH3 + HBr. This is why excess ammonia is used when a primary amine is wanted.
  • Reduction of an amide with LiAlH4: the C=O becomes CH2. CH3CONH2 + 4[H] → CH3CH2NH2 + H2O.
  • Reduction of a nitrile with LiAlH4 or H2/Ni: CH3CN + 4[H] → CH3CH2NH2. A route that adds a carbon (via KCN) and ends in an amine.

Basicity

Like ammonia, amines are Brønsted–Lowry bases: the lone pair on nitrogen accepts a proton. In water they give alkaline solutions:

\[ \mathrm{CH_3CH_2NH_2 + H_2O \rightleftharpoons CH_3CH_2NH_3^{+} + OH^{-}} \]

and they react with acids to form salts: CH3CH2NH2 + HCl → CH3CH2NH3+Cl.

With acyl chlorides, ammonia and amines form amides at room temperature, by addition–elimination (topic 33), a condensation reaction that eliminates HCl.

34.2 Phenylamine and azo compounds

Making phenylamine

  1. Nitrate benzene: concentrated HNO3 and H2SO4, 25–60 °C → nitrobenzene.
  2. Reduce with tin and concentrated HCl, heated under reflux: \[ \mathrm{C_6H_5NO_2 + 6[H] \rightarrow C_6H_5NH_2 + 2H_2O} \] In the acid, the product is present as its salt, C6H5NH3+.
  3. Add NaOH(aq) to release the free amine from its salt: C6H5NH3+ + OH → C6H5NH2 + H2O.

Reactions of phenylamine

  • Bromine water, room temperature: decolourised, with a white precipitate of 2,4,6-tribromophenylamine. Like OH in phenol, the NH2 lone pair feeds electron density into the ring and activates the 2-, 4- and 6-positions. \[ \mathrm{C_6H_5NH_2 + 3Br_2 \rightarrow C_6H_2Br_3NH_2 + 3HBr} \]
  • Nitrous acid (NaNO2 + dilute HCl) below 10 °C → the benzenediazonium salt, C6H5N2+Cl; warming it with water gives phenol and nitrogen (topic 32).

Azo compounds

Benzenediazonium chloride couples with phenol in NaOH(aq) to form an azo compound, containing the azo group, –N=N–, linking two aromatic rings. Because delocalisation extends over both rings and the N=N, these compounds absorb visible light and are brightly coloured: they are widely used as dyes. Other azo dyes are made the same way, by coupling different diazonium salts with different phenols or aromatic amines (for example with naphthol, giving red dyes).

Relative basicity: ethylamine > ammonia > phenylamine

Basicity depends on how available the nitrogen’s lone pair is to accept a proton:

  • Ethylamine: the ethyl group is electron-donating (positive inductive effect), which increases the electron density on nitrogen and makes the lone pair more available. Stronger base than ammonia.
  • Ammonia: no alkyl groups; the reference point.
  • Phenylamine: the lone pair on nitrogen overlaps with the delocalised π system of the ring, so it is partly delocalised into the ring and less available to accept a proton. Much weaker base than ammonia.

34.3 Amides

Amides, RCONH2, are made from an acyl chloride with ammonia (primary amide) or a primary amine (secondary amide, RCONHR′), at room temperature.

  • Hydrolysis with aqueous acid (heat): the carboxylic acid and the ammonium salt. \[ \mathrm{CH_3CONH_2 + H_2O + HCl \rightarrow CH_3COOH + NH_4Cl} \]
  • Hydrolysis with aqueous alkali (heat): the carboxylate salt and ammonia gas. \[ \mathrm{CH_3CONH_2 + NaOH \rightarrow CH_3COONa + NH_3} \]
  • Reduction with LiAlH4: the C=O is reduced to CH2, giving an amine.

Amides are much weaker bases than amines — effectively neutral. The lone pair on nitrogen is delocalised over the N–C=O group, drawn towards the very electronegative carbonyl oxygen. It is therefore not available to accept a proton.

34.4 Amino acids

An α-amino acid has an NH2 and a COOH on the same carbon: H2NCH(R)COOH, where R varies from one amino acid to another (H in glycine, CH3 in alanine).

Zwitterions and the isoelectric point

The molecule contains both an acidic group and a basic group, so it can transfer a proton internally, from COOH to NH2, forming a zwitterion: an ion with both a positive and a negative charge but no overall charge.

\[ \mathrm{H_2NCH(R)COOH \rightleftharpoons {}^{+}H_3NCH(R)COO^{-}} \]

Solid amino acids exist as zwitterions, which is why they are crystalline solids with high melting points and are soluble in water. In solution, the form depends on the pH:

  • in acid (low pH): the COO takes an H+, giving a cation, +H3NCH(R)COOH;
  • in alkali (high pH): the NH3+ loses an H+, giving an anion, H2NCH(R)COO;
  • at the isoelectric point, the pH at which the amino acid exists mainly as the zwitterion, it has no overall charge. Each amino acid has its own isoelectric point (glycine about 6.0; those with extra acidic side chains lower, extra basic side chains higher).
Three forms of glycine. In acid (low pH) it is a cation with an NH3 plus group and COOH. At the isoelectric point it is a zwitterion with NH3 plus and COO minus. In alkali (high pH) it is an anion with NH2 and COO minus.
Glycine in acid, at its isoelectric point, and in alkali.

Peptides

The COOH of one amino acid reacts with the NH2 of another in a condensation reaction, eliminating water and forming an amide (peptide) bond, –CONH–. Two amino acids give a dipeptide, three a tripeptide. Two different amino acids can join in two orders, giving two different dipeptides: glycine + alanine gives Gly-Ala (H2NCH2CONHCH(CH3)COOH) and Ala-Gly.

Electrophoresis

A mixture is placed in the middle of a gel soaked in a buffer of known pH, and a potential difference is applied. Each species moves according to its charge at that pH:

  • if the pH is above its isoelectric point, the amino acid is negative (anion) and moves towards the positive electrode (anode);
  • if the pH is below its isoelectric point, it is positive (cation) and moves towards the negative electrode (cathode);
  • at its isoelectric point it has no net charge and does not move.

How far it moves depends on its charge and size: smaller and more highly charged ions move faster. So a dipeptide typically moves less far than an amino acid with the same charge. The separated spots are made visible with a developing agent (ninhydrin) and identified by comparison with standards.

An electrophoresis strip in a buffer at pH 6.0, with the positive electrode on one side and the negative on the other. Glycine, isoelectric point 6.0, has no net charge and stays at the start. Lysine, isoelectric point 9.7, is positively charged and moves to the cathode. Glutamic acid, isoelectric point 3.2, is negatively charged and moves to the anode.
At pH 6.0 each amino acid moves according to its charge: above its pI it is negative, below it positive.

✏️Worked example

A mixture of glycine (isoelectric point 6.0), lysine (9.7) and glutamic acid (3.2) is separated by electrophoresis in a buffer at pH 6.0. (a) Predict the direction each moves, and explain. (b) Write the structure of glycine at pH 1 and at pH 12. (c) Place ethylamine, ammonia, phenylamine and ethanamide in order of base strength, and explain the position of ethanamide.

(a)

  • Glycine: pH 6.0 is its isoelectric point, so it is a zwitterion with no net charge and stays at the start.
  • Lysine: pH 6.0 is below its isoelectric point, so it is protonated and positive: it moves towards the cathode (negative electrode).
  • Glutamic acid: pH 6.0 is above its isoelectric point, so it has lost a proton and is negative: it moves towards the anode (positive electrode).

(b) At pH 1 (acid): +H3NCH2COOH. At pH 12 (alkali): H2NCH2COO.

(c) ethylamine > ammonia > phenylamine > ethanamide. In ethanamide the nitrogen lone pair is delocalised over the N–C=O group towards the electronegative oxygen, so it is almost unavailable to accept a proton — ethanamide is essentially neutral, weaker even than phenylamine.

Check it. Use the rule in one line: pH above pI → negative → anode; below pI → positive → cathode. Glutamic acid (acidic side chain, low pI) and lysine (basic side chain, high pI) must move in opposite directions at any pH between their two pI values, and they do.
Reversing the electrodes. Negative ions are attracted to the positive electrode. In electrolysis the positive electrode is called the anode, and the same name is used here. Linking “anion” to “anode” is the safest memory aid: anions go to the anode.

📝Practise

Work through these, then reveal the answer. Each question targets a different objective from the list above.

1. Give two ways of making propylamine, CH3CH2CH2NH2, one of which starts from a two-carbon compound.
(1) 1-bromopropane + excess NH3 in ethanol, heated under pressure. (2) Starting from bromoethane: KCN in ethanol, heat → propanenitrile, CH3CH2CN; then reduce with LiAlH4 (or H2/Ni) → CH3CH2CH2NH2. (Reducing propanamide with LiAlH4 also works.)
2. Outline the preparation of phenylamine from benzene, with reagents and conditions.
Step 1: concentrated HNO3 and concentrated H2SO4, 25–60 °C → nitrobenzene. Step 2: tin and concentrated HCl, heat under reflux → phenylammonium ions (C6H5NO2 + 6[H] → C6H5NH2 + 2H2O, the amine being protonated in the acid). Step 3: add NaOH(aq) to liberate the free phenylamine from its salt.
3. Explain why phenylamine is a weaker base than ammonia, and ethylamine a stronger one.
Base strength depends on the availability of the lone pair on N to accept H+. In ethylamine, the electron-donating ethyl group increases the electron density on N, so the lone pair is more available: stronger base. In phenylamine, the lone pair overlaps with the delocalised π system of the ring and is partly delocalised into it, so it is less available: weaker base.
4. Write equations for the hydrolysis of propanamide by (a) dilute HCl; (b) NaOH(aq).
(a) CH3CH2CONH2 + H2O + HCl → CH3CH2COOH + NH4Cl. (b) CH3CH2CONH2 + NaOH → CH3CH2COONa + NH3 (ammonia gas given off on heating, turning damp red litmus blue).
5. Draw the two dipeptides that can form from glycine and alanine, and name the bond formed.
Gly-Ala: H2NCH2CONHCH(CH3)COOH (glycine’s COOH joined to alanine’s NH2). Ala-Gly: H2NCH(CH3)CONHCH2COOH. Each forms by condensation, eliminating one H2O, and contains a peptide (amide) bond, –CONH–.
6. Explain why amino acids have high melting points and dissolve in water, whereas most organic compounds of similar size are liquids.
Amino acids exist as zwitterions, +H3NCH(R)COO. In the solid, these carry full positive and negative charges, so they are held together by strong ionic attractions between neighbouring zwitterions, much stronger than intermolecular forces: high melting points. In water, the charged groups are strongly hydrated (ion–dipole attraction and hydrogen bonding), so they dissolve.

🔗Go deeper — other people’s work

These are external resources, not mine. If one stops working, tell me and everything above it on this page still stands.

  • Chemguide (Jim Clark) — the amines and amino acids sections, including basicity and zwitterions
  • Royal Society of Chemistry — resources on electrophoresis and on making azo dyes